| Post Reply | RetroFed Forum Forum Index » The Far Side |
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m_f
discuss.online
m_f@discuss.onlineJoined: 2024-12-11 |
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OpenStars
discuss.online
OpenStars@discuss.onlineJoined: 2023-12-31 |
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danc4498
lemmy.world
danc4498@lemmy.world Joined: 2023-06-10 |
I wonder how much force that would take to pull. |
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MajorMajormajormajor
lemmy.ca
MajorMajormajormajor@lemmy.ca Joined: 2023-06-12 |
I wonder how much force that would take to pull.
Depends on how deep the person is, but since they're scuba diving in somewhat shallow waters (no wet suit, at the bottom but can see, etc.) not a terribly high amount. If we assume 50 metre depth and 1 metre diametre plug: p=ρ×g×h+p0 = 1022 kg/m3(9.8m/s2)(50m)+101kPa = 602 kPa or 87 psi for you Americans. Area plug = πr2 = π(0.5m)2 = 0.785 m2 F = PA = 602 kPa x 0.785m2 = 472.6 kN or 106 238 lbf So, far above what a person could pull, but not absurd amounts considering the sizes involved. Edit: fucked up my units and force formula, whoopsie. |
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danc4498
lemmy.world
danc4498@lemmy.world Joined: 2023-06-10 |
Depends on how deep the person is, but since they're scuba diving in somewhat shallow waters (no wet suit, at the bottom but can see, etc.) not a terribly high amount. If we assume 50 metre depth and 1 metre diametre plug: p=ρ×g×h+p0 = 1022 kg/m3(9.8m/s2)(50m)+101kPa = 602 kPa or 87 psi for you Americans. Area plug = πr2 = π(0.5m)2 = 0.785 m2 F = PA = 602 kPa x 0.785m2 = 472.6 kN or 106 238 lbf...
If I'm ever in this situation, I'll bring some friends. |
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bumblefumble
feddit.dk
bumblefumble@feddit.dk Joined: 2026-09-19 |
Depends on how deep the person is, but since they're scuba diving in somewhat shallow waters (no wet suit, at the bottom but can see, etc.) not a terribly high amount. If we assume 50 metre depth and 1 metre diametre plug: p=ρ×g×h+p0 = 1022 kg/m3(9.8m/s2)(50m)+101kPa = 602 kPa or 87 psi for you Americans. Area plug = πr2 = π(0.5m)2 = 0.785 m2 F = PA = 602 kPa x 0.785m2 = 472.6 kN or 106 238 lbf...
You mean kN / lbf for the final answer. |
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toynbee
piefed.social
toynbee@piefed.social Joined: 2025-09-12 |
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MajorMajormajormajor
lemmy.ca
MajorMajormajormajor@lemmy.ca Joined: 2023-06-12 |
You mean kN / lbf for the final answer.
You're absolutely correct, good eye. |
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MajorMajormajormajor
lemmy.ca
MajorMajormajormajor@lemmy.ca Joined: 2023-06-12 |
https://what-if.xkcd.com/53/
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psud
aussie.zone
psud@aussie.zone Joined: 2023-07-26 |
Depends on how deep the person is, but since they're scuba diving in somewhat shallow waters (no wet suit, at the bottom but can see, etc.) not a terribly high amount. If we assume 50 metre depth and 1 metre diametre plug: p=ρ×g×h+p0 = 1022 kg/m3(9.8m/s2)(50m)+101kPa = 602 kPa or 87 psi for you Americans. Area plug = πr2 = π(0.5m)2 = 0.785 m2 F = PA = 602 kPa x 0.785m2 = 472.6 kN or 106 238 lbf...
It also depends on what's on the other side. It might not be vacuum, though whatever it wouldn't likely be in the hundreds of kilonewtons |
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psud
aussie.zone
psud@aussie.zone Joined: 2023-07-26 |
I wonder where the other end of the chain is |
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fartographer
lemmy.world
fartographer@lemmy.world Joined: 2025-06-29 |
I wonder how much force that would take to pull.
Crab pipe. 'Nuff said |
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🌞 Alexander Daychilde 🌞
lemmy.world
daychilde@lemmy.worldJoined: 2023-06-13 |
It also depends on what's on the other side. It might not be vacuum, though whatever it wouldn't likely be in the hundreds of kilonewtons
But what if it's dusty under there? |
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