| Post Reply | RetroFed Forums Forum Index » Comic Strips |
| Author | Message | ||
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m_f
discuss.online
m_f@discuss.onlineJoined: 2024-12-11 |
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Dadifer
lemmy.world
Dadifer@lemmy.world Joined: 2023-08-04 |
Wild |
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Joelk111
lemmy.world
Joelk111@lemmy.worldJoined: 2023-07-01 |
Should've been "do you have protection?" or something for the last line I feel like. |
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| 10 | |||
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folekaule
lemmy.world
folekaule@lemmy.world Joined: 2023-06-20 |
I feel like "I wanna do it" as her last line would have been a little funnier. |
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hakunawazo
lemmy.world
hakunawazo@lemmy.world Joined: 2023-10-02 |
Icarus origin story |
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| 5 | |||
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inbn
lemmy.zip
inbn@lemmy.zip Joined: 2025-07-07 |
Up (NSFW) |
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| 11 | |||
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ab60753
lemmy.zip
ab60753@lemmy.zip Joined: 2026-06-28 |
So... hear me out. Yes i know its just a comic... im just autistic. Soooo... Assuming the guy is average weight (70 kg) the total force of gravity on him is F~g~=70×g N. The force of boyancy would be F~boyancy~=d~helium~×V~displacemwnt~×g N. If thease are in equilibrium (the guy floats): d~helium~×V~displacemwnt~× If d~helium~ is 0.178 kg/m^3^ then Like i know condoms are super strechy (can hold about 40L air befor burating) but wow. Thats like a phone booth per condom. Did you need this info?... no. Was i compelled to calculate this? ... no .... stay in school kids. |
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| 9 | |||
tetris11
feddit.uk
tetris11@feddit.ukJoined: 2025-02-17 |
So... hear me out. Yes i know its just a comic... im just autistic. Soooo... Assuming the guy is average weight (70 kg) the total force of gravity on him is F~g~=70×g N. The force of boyancy would be F~boyancy~=d~helium~×V~displacemwnt~×g N. If thease are in equilibrium (the guy floats): F~boyancy~=F~g~ d~helium~×V~displacemwnt~×g =70×g If d~helium~ is 0.178 kg/m^3^ then 70/0.178 = V~displacemw...
What if he used Hydrogen though |
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CannonFodder
lemmy.world
CannonFodder@lemmy.world Joined: 2025-08-22 |
What if he used Hydrogen though
Hardly matters as the salient amount is the weight of the displaced air, not the weight of the helium or hydrogen. However using hydrogen might lead to a nice flameout. |
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DagwoodIII
piefed.social
DagwoodIII@piefed.social Joined: 2025-06-17 |
So... hear me out. Yes i know its just a comic... im just autistic. Soooo... Assuming the guy is average weight (70 kg) the total force of gravity on him is F~g~=70×g N. The force of boyancy would be F~boyancy~=d~helium~×V~displacemwnt~×g N. If thease are in equilibrium (the guy floats): F~boyancy~=F~g~ d~helium~×V~displacemwnt~×g =70×g If d~helium~ is 0.178 kg/m^3^ then 70/0.178 = V~displacemw...
Classic rookie mistake. Not every store has an unlimited supply of condoms, especially the extra large ones*. He brought 200 at her store, and emptied the shelves. He probably hit a dozen places and brought all they had on hand. *I shall modestly refrain from enumerating the many, many times I myself have needed to purchase a vast number of extra large condoms... |
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NoneOfUrBusiness
fedia.io
NoneOfUrBusiness@fedia.ioJoined: 2024-06-13 |
So... hear me out. Yes i know its just a comic... im just autistic. Soooo... Assuming the guy is average weight (70 kg) the total force of gravity on him is F~g~=70×g N. The force of boyancy would be F~boyancy~=d~helium~×V~displacemwnt~×g N. If thease are in equilibrium (the guy floats): F~boyancy~=F~g~ d~helium~×V~displacemwnt~×g =70×g If d~helium~ is 0.178 kg/m^3^ then 70/0.178 = V~displacemw...
I'm sorry to say this, but your autism has failed you. Buoyancy is proportional not to the mass inside the displaced volume, but to the displaced mass, which is to say the difference between the mass inside the displaced volume and the mass of the medium that would've otherwise occupied it. In this case that means Fbuoyancy=g(dair-dhelium)Vdisplacement. The density of air is about 1.23kg/m³, so your answer six times too big. |
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DagwoodIII
piefed.social
DagwoodIII@piefed.social Joined: 2025-06-17 |
Up (NSFW)
You are an ignorant child. There was a NSFW version of 'Up' long before the animated one. You're welcome. https://youtu.be/Pkn1bVOE8H8 |
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wolframhydroxide
sh.itjust.works
wolframhydroxide@sh.itjust.works Joined: 2024-07-25 |
Hardly matters as the salient amount is the weight of the displaced air, not the weight of the helium or hydrogen. However using hydrogen might lead to a nice flameout.
No, what matters is the comparative density, and you must calculate the total mass of the air displaced, as well as the mass of the gas being used to displace it. Hydrogen is half as dense as helium. While helium has a density of 4g/22.4L, air has an approximate density (assuming 3% water content) of about 29g/22.4L, by my calculations. So, helium is just under 1/7th the density of air, but hydrogen is less than 1/14th the density of air. Is it a tiny mass difference? Actually, no, it's quite significant. Hold for calculations. |
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