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XXL [SMBC]
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m_‮f discuss.online m_f@discuss.online
Joined: 2024-12-11
Quote

cross-posted from: https://discuss.online/post/47437499

http://www.smbc-comics.com/comic/xxl

::: spoiler Alt text
I haven't dated in a long time, so this may be unrealistic.
:::

::: spoiler Bonus panel
Bonus panel
:::

242   Original
Dadifer lemmy.world Dadifer@lemmy.world
Joined: 2023-08-04
#2 · Quote Reply

Wild

4
Joelk111 lemmy.world Joelk111@lemmy.world
Joined: 2023-07-01
#3 · Quote Reply

Should've been "do you have protection?" or something for the last line I feel like.

10
folekaule lemmy.world folekaule@lemmy.world
Joined: 2023-06-20
#4 · Quote Reply

I feel like "I wanna do it" as her last line would have been a little funnier.

2
hakunawazo lemmy.world hakunawazo@lemmy.world
Joined: 2023-10-02
#5 · Quote Reply

Icarus origin story

5
inbn lemmy.zip inbn@lemmy.zip
Joined: 2025-07-07
#6 · Quote Reply

Up (NSFW)

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ab60753 lemmy.zip ab60753@lemmy.zip
Joined: 2026-06-28
#7 · (edited) Quote Reply

So... hear me out. Yes i know its just a comic... im just autistic. Soooo...

Assuming the guy is average weight (70 kg) the total force of gravity on him is F~g~=70×g N. The force of boyancy would be F~boyancy~=d~helium~×V~displacemwnt~×g N.

If thease are in equilibrium (the guy floats):
F~boyancy~=F~g~

d~helium~×V~displacemwnt~×g =70×g

If d~helium~ is 0.178 kg/m^3^ then
70/0.178 = V~displacemwnt~= 393.5 m^3^≈ 1.9 m^3^ per condom.

Like i know condoms are super strechy (can hold about 40L air befor burating) but wow. Thats like a phone booth per condom.

Did you need this info?... no. Was i compelled to calculate this? ... no .... stay in school kids.

9
tetris11 feddit.uk tetris11@feddit.uk
Joined: 2025-02-17
#8 · Quote Reply

So... hear me out. Yes i know its just a comic... im just autistic. Soooo... Assuming the guy is average weight (70 kg) the total force of gravity on him is F~g~=70×g N. The force of boyancy would be F~boyancy~=d~helium~×V~displacemwnt~×g N. If thease are in equilibrium (the guy floats): F~boyancy~=F~g~ d~helium~×V~displacemwnt~×g =70×g If d~helium~ is 0.178 kg/m^3^ then 70/0.178 = V~displacemw...

What if he used Hydrogen though

4
CannonFodder lemmy.world CannonFodder@lemmy.world
Joined: 2025-08-22
#9 · Quote Reply

What if he used Hydrogen though

Hardly matters as the salient amount is the weight of the displaced air, not the weight of the helium or hydrogen. However using hydrogen might lead to a nice flameout.

3
DagwoodIII piefed.social DagwoodIII@piefed.social
Joined: 2025-06-17
#10 · Quote Reply

So... hear me out. Yes i know its just a comic... im just autistic. Soooo... Assuming the guy is average weight (70 kg) the total force of gravity on him is F~g~=70×g N. The force of boyancy would be F~boyancy~=d~helium~×V~displacemwnt~×g N. If thease are in equilibrium (the guy floats): F~boyancy~=F~g~ d~helium~×V~displacemwnt~×g =70×g If d~helium~ is 0.178 kg/m^3^ then 70/0.178 = V~displacemw...

Classic rookie mistake.

Not every store has an unlimited supply of condoms, especially the extra large ones*.

He brought 200 at her store, and emptied the shelves. He probably hit a dozen places and brought all they had on hand.

*I shall modestly refrain from enumerating the many, many times I myself have needed to purchase a vast number of extra large condoms...

2
NoneOfUrBusiness fedia.io NoneOfUrBusiness@fedia.io
Joined: 2024-06-13
#11 · Quote Reply

So... hear me out. Yes i know its just a comic... im just autistic. Soooo... Assuming the guy is average weight (70 kg) the total force of gravity on him is F~g~=70×g N. The force of boyancy would be F~boyancy~=d~helium~×V~displacemwnt~×g N. If thease are in equilibrium (the guy floats): F~boyancy~=F~g~ d~helium~×V~displacemwnt~×g =70×g If d~helium~ is 0.178 kg/m^3^ then 70/0.178 = V~displacemw...

I'm sorry to say this, but your autism has failed you. Buoyancy is proportional not to the mass inside the displaced volume, but to the displaced mass, which is to say the difference between the mass inside the displaced volume and the mass of the medium that would've otherwise occupied it. In this case that means Fbuoyancy=g(dair-dhelium)Vdisplacement. The density of air is about 1.23kg/m³, so your answer six times too big.

4
DagwoodIII piefed.social DagwoodIII@piefed.social
Joined: 2025-06-17
#12 · Quote Reply

Up (NSFW)

You are an ignorant child.

There was a NSFW version of 'Up' long before the animated one.

You're welcome.

https://youtu.be/Pkn1bVOE8H8

1
wolframhydroxide sh.itjust.works wolframhydroxide@sh.itjust.works
Joined: 2024-07-25
#13 · Quote Reply

Hardly matters as the salient amount is the weight of the displaced air, not the weight of the helium or hydrogen. However using hydrogen might lead to a nice flameout.

No, what matters is the comparative density, and you must calculate the total mass of the air displaced, as well as the mass of the gas being used to displace it. Hydrogen is half as dense as helium. While helium has a density of 4g/22.4L, air has an approximate density (assuming 3% water content) of about 29g/22.4L, by my calculations. So, helium is just under 1/7th the density of air, but hydrogen is less than 1/14th the density of air. Is it a tiny mass difference? Actually, no, it's quite significant. Hold for calculations.

1
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