| Post Reply | RetroFed Forum Forum Index » Science Memes |
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the_beber
feddit.org
the_beber@feddit.org Joined: 2025-06-24 |
The idea to make this popped in my mind, when I did an experiment using one of these a while ago. Bonus: .xcf file |
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Thorry
feddit.org
Thorry@feddit.org Joined: 2025-08-30 |
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einfach_orangensaft
sh.itjust.works
einfach_orangensaft@sh.itjust.worksJoined: 2024-04-08 |
quality meme |
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the_beber
feddit.org
the_beber@feddit.org Joined: 2025-06-24 |
Oh no… I just noticed an additional |
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jaydev
lemmy.world
jaydev@lemmy.worldJoined: 2023-06-18 |
I feel like I should know this meme, but don't. I have 3 main questions:
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the_beber
feddit.org
the_beber@feddit.org Joined: 2025-06-24 |
I feel like I should know this meme, but don't. I have 3 main questions: Why does the multiplication of the 2 signals result in an extra fluctuation in the product? Why would the low pass filter produce a flat line? Is it because it's letting such low frequencies pass that none of the frequencies in the product signal are not included? What does this have to do with locking in?
The device, I‘m referencing here is called a lock-in amplifier. Here‘s a great write up on the priciples of this technique: https://www.zhinst.com/sites/default/files/documents/2025-10/zi_whitepaper_principles_of_lock-in_detection.pdf But TLDR: After the reference signal is adjusted to have same frequency (and therefore constant phase difference), you get a signal that oscillates with |
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BigDanishGuy
sh.itjust.works
BigDanishGuy@sh.itjust.works Joined: 2023-07-03 |
TBH it's been more than a decade since I graduated electronics engineering, I really didn't like filter theory, so I went with embedded electronics for my specialization, and went to work in an entirely different field so... What's the purpose of this filter, if all you're getting out is DC? I mean wouldn't you want to set the cutoff frequency high enough to actually get a signal through? If all you're looking for is the DC component, then wouldn't you be better off (as in a more simple, thus cheaper, solution) just doing a rolling average filter? Again, I really didn't follow along in signal processing that well, so I may just be exposing my ignorance here. |
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the_beber
feddit.org
the_beber@feddit.org Joined: 2025-06-24 |
TBH it's been more than a decade since I graduated electronics engineering, I really didn't like filter theory, so I went with embedded electronics for my specialization, and went to work in an entirely different field so... What's the purpose of this filter, if all you're getting out is DC? I mean wouldn't you want to set the cutoff frequency high enough to actually get a signal through? If al...
The (effective) low-pass is only applied after the signals have been multiplied. This filters out the signal with the same frequency (and phase) as the reference. I have a more detailed comment on how this works in response to another person here in this comment section. |
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