Goal: a program that takes a char as input and outputs which char has been inputted and the humber of line(s). The below code makes the program output the inputted char twice: once - I assume - as a result of how getchar() works and once as a result of printf(). Is there any way to do this more elegantly, as in, not displaying the inputted char twice? If possible, keep to while, without suggesting for.

PS: the repetition of getchar() is just my ugly way of removing the trailing '\n'.

#include <stdio.h>  

int main(void)  
{  
        int c, nl;  
        c = 0;  
        nl = 0;  

        while ((c = getchar()) != EOF) {  
                getchar();  
                printf("%c, %d\n", c, nl);  
                ++nl;  
        }  
}  

The first char appears because your terminal is echoing back what you are typing in.
This is the default, and you see it also in most other programs, with password inputs as a big exception. Those tell the terminal in some way that it should disable the echo functionality, and turn it back on after the password has been read.
see https://stackoverflow.com/questions/59922972/how-to-stop-echo-in-terminal-using-c for more info

Nice! Thanks so much! :)